Most of you’re acquainted with the components:

s1 x k1 = z1 + r1 x d1 mod n

When you have two of them associated like this:

s1 x k1 = z1 + r1 x d1 mod n (1)

s2 x k1 = z2 + r1 x d1 mod n (2)

There’s the components:

(s1 – s2) x k1 = (z1 – z2) mod n (3)

to search out,k1.And from that d1.

There additionally particular instances then you will discover d1,from the components:

k2 = k1 – 1 or m,m < n (or)

k2 = k1 /2 or m,m < n.

Additionally,i learn in lots of posts right here,that k1 and k2 or (in particular instances) d1 and d2,can’t be associated in a algebric and logic method,beacouse after all,will likely be a components that can discover k1,k2,d1 and d2.
Now,i discovered with a easy derivation a components:

s1 x k1 = z1 + r1 x d1 (4)

s2 x k2 = z2 + r2 x d1 (5)

a x k1 – b x k2 = c (6)

Now the paradox,from my standpoint:

I admit that my superior algebra is weak,however i need to ensure that if somebody is healthier then me
will help me to show i’m proper or show me mistaken and assist me and in the long run allow you to,the reader.

I can show with out,that i name invisible information/stealth information,that this components is true.By invisible information /stealth information,i imply to have two actual or synthetic tx (transactions),the place i can use invisible information aka actual worth of k1,k2 or d1,to test the data immediately.

However right here is the factor: even i can show in any transactions wherever,relation between a x k1 and b x k2 is c,by way of numbers,logic and components(4),(5) and (6) solely,with out invisible information,i can’t extract k1,k2 or d,even in a two associated k1,k2 transaction made public right here on this discussion board.

I attempted two modes to extract k1,k2 or d,nevertheless it gave me zero division.
Why,if i can show with algebra and logic which might be associated?

I believe first as a result of my superior algebra isn’t excessive sufficient or second is usually a rule that may not be damaged associated with how these equations are made.Are you able to assist me?

Be aware.I’m conscious that this sort of information is extremely delicate.For that i not made public how i can show with out invisible information,how can k1 and k2 are associated by way of (4),(5) and (6).However as you anticipate with a little bit of considering you are able to do,too.If somebody can provide me the reply in personal,please do.